16. the body of a 154 - pound person contains approximately 2×10⁻¹ milligrams of gold and 6×10¹ milligrams…
16. the body of a 154 - pound person contains approximately 2×10⁻¹ milligrams of gold and 6×10¹ milligrams of aluminum. based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body? enter your answer in the box.\n17\nstop
Answer
Explanation:
Step1: Identificar las cantidades
La cantidad de oro es $2\times10^{- 1}$ miligramos y la cantidad de aluminio es $6\times10^{1}$ miligramos.
Step2: Calcular el factor
Dividimos la cantidad de aluminio entre la cantidad de oro: $\frac{6\times10^{1}}{2\times10^{-1}}$. Usando las reglas de exponentes $\frac{a^{m}}{a^{n}}=a^{m - n}$ y $\frac{a}{b}\times\frac{c}{d}=\frac{ac}{bd}$, tenemos $\frac{6}{2}\times\frac{10^{1}}{10^{-1}} = 3\times10^{1-(-1)}=3\times10^{2}=300$.
Answer:
300