3 a baker adds baking powder onto a food scale by teaspoons. the scale has marks every \\(\\frac{1}{10}\\)…

3 a baker adds baking powder onto a food scale by teaspoons. the scale has marks every \\(\\frac{1}{10}\\) g. each teaspoon of baking powder weighs 3.81 g. between which two marks on the scale will the weight be after the seventh teaspoon is added to the scale? show your work.
Answer
Explanation:
Step1: Calculate total weight
Multiply teaspoons (7) by per - tsp weight (3.81g).
$7\times3.81 = 26.67$ g
Step2: Analyze scale marks
Scale marks are at multiples of $\frac{1}{10}=0.1$ g.
Find integers $n$ where $n\times0.1<26.67<(n + 1)\times0.1$? Wait, no—wait, 26.67 is between $26.6$ (266×0.1) and $26.7$ (267×0.1), since $26.6 = \frac{266}{10}$ and $26.7=\frac{267}{10}$, and $26.6<26.67<26.7$.
Answer:
Between the marks for $26.6$ g (or $\frac{266}{10}$ g) and $26.7$ g (or $\frac{267}{10}$ g).