consider the following method that is intended to modify its parameter namelist by replacing all occurrences…

consider the following method that is intended to modify its parameter namelist by replacing all occurrences of name with newvalue.\npublic void replace(arraylist<string> namelist, string name, string newvalue)\n{\n for (int j = 0; j < namelist.size(); j++)\n {\n if ( /* expression */ )\n {\n namelist.set(j, newvalue);\n }\n }\n}\nwhich of the following can be used to replace /* expression */ so that replace will work as intended?\na.\nnamelist.get(j).equals(name)\nb.\nnamelist.get(j) == name\nc.\nnamelist.remove(j)\nd.\nnamelistj == name

consider the following method that is intended to modify its parameter namelist by replacing all occurrences of name with newvalue.\npublic void replace(arraylist<string> namelist, string name, string newvalue)\n{\n for (int j = 0; j < namelist.size(); j++)\n {\n if ( /* expression */ )\n {\n namelist.set(j, newvalue);\n }\n }\n}\nwhich of the following can be used to replace /* expression */ so that replace will work as intended?\na.\nnamelist.get(j).equals(name)\nb.\nnamelist.get(j) == name\nc.\nnamelist.remove(j)\nd.\nnamelistj == name

Answer

Brief Explanations:

To determine the correct expression, we analyze each option:

  • Option A: In Java, to compare the contents of two Strings, we use the equals() method. nameList.get(j).equals(name) checks if the String at index j in nameList has the same content as name, which is correct for replacing occurrences.
  • Option B: The == operator in Java compares object references, not the content of Strings. So this would not correctly identify when the String content matches.
  • Option C: nameList.remove(j) is a method to remove an element, not to check for a match. This is irrelevant to the condition needed.
  • Option D: nameList[j] is not valid syntax for accessing elements in an ArrayList in Java (we use get(j)), and again == is incorrect for String content comparison.

Answer:

A. nameList.get(j).equals(name)