a cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. if the basin is completely filled…

a cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. if the basin is completely filled with water, how much water will it hold? round the answer to the nearest tenth of a foot. \\boxed{} ft³

a cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. if the basin is completely filled with water, how much water will it hold? round the answer to the nearest tenth of a foot. \\boxed{} ft³

Answer

Explanation:

Step1: Find the radius of the cylinder

The diameter is 5 feet, so the radius ( r = \frac{5}{2}= 2.5 ) feet.

Step2: Recall the formula for the volume of a cylinder

The volume ( V ) of a cylinder is given by ( V=\pi r^{2}h ), where ( r ) is the radius and ( h ) is the height. Here, ( h = 2 ) feet.

Step3: Substitute the values into the formula

Substitute ( r = 2.5 ) and ( h = 2 ) into the formula: ( V=\pi\times(2.5)^{2}\times2 ). First, calculate ( (2.5)^{2}=6.25 ). Then, ( V=\pi\times6.25\times2= 12.5\pi ). Using ( \pi\approx3.14159 ), we get ( V\approx12.5\times3.14159 = 39.269875 ).

Step4: Round to the nearest tenth

Rounding ( 39.269875 ) to the nearest tenth gives ( 39.3 ).

Answer:

( 39.3 )