what missing condition will give you the output shown?\nnumb = 2\nwhile ______:\n numb = numb +…

what missing condition will give you the output shown?\nnumb = 2\nwhile ______:\n numb = numb + 3\nprint(numb)\noutput: 14\nnumb > 10\nnumb < 12\nnumb > 12\nnumb < 10

what missing condition will give you the output shown?\nnumb = 2\nwhile ______:\n numb = numb + 3\nprint(numb)\noutput: 14\nnumb > 10\nnumb < 12\nnumb > 12\nnumb < 10

Answer

Explanation:

Step1: Analyze initial value

Initial numB = 2.

Step2: Determine increment process

Each iteration, numB is incremented by 3.

Step3: Find number of iterations

Let the number of iterations be $n$. We have the equation $2 + 3n=14$. Solving for $n$: $3n=14 - 2=12$, so $n = 4$. After 4 iterations, numB becomes 14. The loop should stop when numB reaches 14. So the condition should be such that the loop continues until just before numB exceeds 12.

Answer:

numB < 12