note: please make sure to properly format your answers. all dollar figures in the answers need to include…

note: please make sure to properly format your answers. all dollar figures in the answers need to include the dollar sign and any amount over 1,000 should include the comma ($2,354.67). all percentage values in the answers need to include a percentage sign (%). for all items without specific rounding instructions, round your answers to two decimal places, show both decimal places (5.06).\nair - conditioners are rated by btus. you learned about btus in section 7 - 2. example 6. one watt - hour is equivalent to 3.413 btus per hour.\na. how many btus per hour are equivalent to a kilowatt - hour?\nb. if an air conditioner is rated at 16,000 btus per hour, how many watts does it require? round to the nearest 100 watts.\nc. express your answer to part b in kilowatt - hours.\nd. if you run an air conditioner for 18 hours per day for 31 days in july, how many kilowatt - hours will it require for the month? round to the nearest 100 kilowatt - hours.\ne. based on your answer to part d, and a rate of $0.13 per kilowatt - hour, estimate the cost of running the air conditioner for july to the nearest ten dollars.
Answer
Explanation:
Step1: Convert kilowatt - hour to watt - hour
1 kilowatt - hour = 1000 watt - hour. Since 1 watt - hour = 3.413 BTUs per hour, for 1 kilowatt - hour, the number of BTUs is $1000\times3.413$. $1000\times3.413 = 3413$ BTUs per hour.
Step2: Calculate watts for 16000 BTUs per hour
If 1 watt - hour = 3.413 BTUs per hour, then the number of watts $W$ for 16000 BTUs per hour is $W=\frac{16000}{3.413}\approx4690.89$ watts. Rounding to the nearest 100 watts, it is 4700 watts.
Step3: Convert watts to kilowatt - hours for part b
Since 1 kilowatt = 1000 watts, from 4700 watts, the number of kilowatt - hours is $\frac{4700}{1000}=4.7$ kilowatt - hours.
Step4: Calculate total kilowatt - hours for July
The air - conditioner runs 18 hours per day for 31 days. From part b, it uses 4.7 kilowatt - hours per hour. So the total kilowatt - hours $E$ is $E = 4.7\times18\times31=4.7\times558 = 2622.6$ kilowatt - hours. Rounding to the nearest 100 kilowatt - hours, it is 2600 kilowatt - hours.
Step5: Calculate cost for July
The rate is $0.13 per kilowatt - hour. From part d, the total kilowatt - hours is 2600. So the cost $C$ is $C=0.13\times2600 = 338$ dollars. Rounding to the nearest ten dollars, it is $340.
Answer:
a. 3413 b. 4700 c. 4.7 d. 2600 e. $340