what is the output of this program? numa = 2 numb = 3 if numa == 2 or numb == 2: print(\yes\) elif numa == 2…
what is the output of this program? numa = 2 numb = 3 if numa == 2 or numb == 2: print(\yes\) elif numa == 2 and numb == 3: print(\no\) output:
Answer
Explanation:
Step1: Check if - condition
The condition numA == 2 or numB == 2 is checked first. Given numA = 2 and numB = 3, since numA == 2 is True, the 'or' condition is True.
Step2: Determine output
Since the first - if condition is True, the program will execute the print("yes") statement and skip the elif block.
Answer:
yes