4. what is the output for y?\ny = 0\nfor i in range(0, 8):\n y += i\nprint(y)\n28\n8\n1 2 3 4 5 6 7 8\n0 1 2…

4. what is the output for y?\ny = 0\nfor i in range(0, 8):\n y += i\nprint(y)\n28\n8\n1 2 3 4 5 6 7 8\n0 1 2 3 4 5 6 7\n0

4. what is the output for y?\ny = 0\nfor i in range(0, 8):\n y += i\nprint(y)\n28\n8\n1 2 3 4 5 6 7 8\n0 1 2 3 4 5 6 7\n0

Answer

Explanation:

Step1: Understand range function

The range(0, 8) generates a sequence of numbers from 0 to 7 (not including 8).

Step2: Analyze the loop

The loop iterates through each number i in the range. Initially y = 0, and in each iteration y is updated as y=y + i. So we need to sum up the numbers from 0 to 7.

Step3: Use sum formula

The sum of an arithmetic - series (S_n=\sum_{k = 0}^{n - 1}k=\frac{n(n - 1)}{2}), where (n = 8) here. Substituting (n = 8) into the formula, we get (S=\frac{7\times(7 + 1)}{2}=\frac{7\times8}{2}=28).

Answer:

A. 28