question 7 (4 points)\n3 minutes given the code 1101011001, what would be the parity bit given even…

question 7 (4 points)\n3 minutes given the code 1101011001, what would be the parity bit given even parity?\nthe hamming code consists of both data bits and parity bits. given the hamming code consists of 8 parity bits, what is the maximum number of data bits the hamming code can carry?

question 7 (4 points)\n3 minutes given the code 1101011001, what would be the parity bit given even parity?\nthe hamming code consists of both data bits and parity bits. given the hamming code consists of 8 parity bits, what is the maximum number of data bits the hamming code can carry?

Answer

Explanation:

Step1: Calculate parity bit for 1101011001

Count the number of 1s in 1101011001. There are 6 1s. For even - parity, since the number of 1s is already even, the parity bit is 0.

Step2: Calculate maximum data bits for Hamming code with 8 parity bits

The formula for the relationship between the number of data bits $d$ and the number of parity bits $p$ in a Hamming code is $2^p\geq d + p+ 1$. We want to find $d$ when $p = 8$. We can rewrite the formula as $d\leq2^p - p - 1$. Substitute $p = 8$ into the formula: $d\leq2^8-8 - 1=256 - 8 - 1 = 247$.

Answer:

0 247