a 7.00 kg bowling ball is held 2.00 m above the ground. using g = 9.80 m/s², how much energy does the…

a 7.00 kg bowling ball is held 2.00 m above the ground. using g = 9.80 m/s², how much energy does the bowling ball have due to its position?\n68.6 j\n137 j\n274 j\n960 j

a 7.00 kg bowling ball is held 2.00 m above the ground. using g = 9.80 m/s², how much energy does the bowling ball have due to its position?\n68.6 j\n137 j\n274 j\n960 j

Answer

Explanation:

Step1: Identify the formula

The energy due to position is gravitational - potential energy, and the formula is $U = mgh$, where $m$ is mass, $g$ is acceleration due to gravity, and $h$ is height.

Step2: Substitute the given values

Given $m = 7.00\ kg$, $g=9.80\ m/s^{2}$, and $h = 2.00\ m$. Substitute into the formula: $U=(7.00\ kg)\times(9.80\ m/s^{2})\times(2.00\ m)$.

Step3: Calculate the result

$U = 7\times9.8\times2=137.2\ J\approx137\ J$.

Answer:

137 J