001 (part 1 of 2) 10.0 points\na runner is jogging in a straight line at a steady $v_r = 2.3$ km/hr. when…

001 (part 1 of 2) 10.0 points\na runner is jogging in a straight line at a steady $v_r = 2.3$ km/hr. when the runner is $l = 2.1$ km from the finish line, a bird begins flying straight from the runner to the finish line at $v_b = 6.9$ km/hr (3 times as fast as the runner). when the bird reaches the finish line, it turns around and flies directly back to the runner.\nwhat cumulative distance does the bird travel? even though the bird is a dodo, assume that it occupies only one point in space (a \zero\ length bird), travels in a straight line, and that it can turn without loss of speed.\nanswer in units of km.
Answer
Explanation:
Step1: Find the time it takes for the runner to reach the finish - line
The time (t) for the runner to reach the finish - line is determined by the formula (t=\frac{d}{v}), where (d = L=2.1) km is the distance of the runner from the finish - line and (v = v_r = 2.3) km/hr is the runner's speed. So (t=\frac{L}{v_r}).
Step2: Calculate the distance the bird travels
The bird is in flight for the same amount of time (t) as the runner takes to reach the finish - line. The speed of the bird is (v_b = 6.9) km/hr. Using the formula (d=v\times t), and substituting (t=\frac{L}{v_r}) into it, we get (d_b=v_b\times t=v_b\times\frac{L}{v_r}). Substitute (v_r = 2.3) km/hr, (v_b = 6.9) km/hr and (L = 2.1) km into the formula: [d_b=\frac{v_b}{v_r}\times L=\frac{6.9}{2.3}\times2.1] [d_b = 3\times2.1=6.3] km
Answer:
6.3