0.050\\frac{g\\cdot m^{2}}{s^{2}}\\cdot\\square=?\\frac{kg\\cdot m^{2}}{s^{2}}

0.050\\frac{g\\cdot m^{2}}{s^{2}}\\cdot\\square=?\\frac{kg\\cdot m^{2}}{s^{2}}

0.050\\frac{g\\cdot m^{2}}{s^{2}}\\cdot\\square=?\\frac{kg\\cdot m^{2}}{s^{2}}

Answer

Explanation:

Step1: Recall unit - conversion factor

We know that $1\ kg = 1000\ g$, or $1\ g=\frac{1}{1000}\ kg = 10^{- 3}\ kg$.

Step2: Set up the conversion

Let the unknown factor be $x$. We have the equation $0.050\frac{g\cdot m^{2}}{s^{2}}\times x=\frac{kg\cdot m^{2}}{s^{2}}$. Substituting $g = 10^{-3}kg$ into the left - hand side, we get $0.050\times10^{-3}\frac{kg\cdot m^{2}}{s^{2}}\times x=\frac{kg\cdot m^{2}}{s^{2}}$.

Step3: Solve for $x$

To solve for $x$, we can rewrite the equation as $x=\frac{1}{0.050\times10^{-3}}$. First, $0.050\times10^{-3}=5\times10^{-5}$. Then $x = \frac{1}{5\times10^{-5}}=2\times10^{4}$.

Answer:

$2\times10^{4}$