a -0.06 c charge is placed is in a uniform electric field with a strength of 200 n/c. what is the magnitude…

a -0.06 c charge is placed is in a uniform electric field with a strength of 200 n/c. what is the magnitude and direction of the force on the charge?\n12 n in the opposite direction of the field\n12 n in the same direction of the field\n3333 n up in the opposite direction of the field\n3333 n in the same direction of the field

a -0.06 c charge is placed is in a uniform electric field with a strength of 200 n/c. what is the magnitude and direction of the force on the charge?\n12 n in the opposite direction of the field\n12 n in the same direction of the field\n3333 n up in the opposite direction of the field\n3333 n in the same direction of the field

Answer

Explanation:

Step1: Recall the force - field formula

The formula for the force on a charge in an electric field is $F = qE$, where $F$ is the force, $q$ is the charge, and $E$ is the electric - field strength.

Step2: Calculate the magnitude of the force

Given $q=- 0.06\ C$ and $E = 200\ N/C$. Substitute the values into the formula: $F=\vert q\vert E=\vert - 0.06\vert\times200 = 12\ N$.

Step3: Determine the direction of the force

A negative charge experiences a force in the opposite direction of the electric field. Since the charge $q=-0.06\ C$ is negative, the force is in the opposite direction of the field.

Answer:

12 N in the opposite direction of the field