a 7.2×10⁻⁵ c charge has an electric potential energy of 1.08×10⁻² j. the electric potential, to the nearest…

a 7.2×10⁻⁵ c charge has an electric potential energy of 1.08×10⁻² j. the electric potential, to the nearest whole number, is v.
Answer
Explanation:
Step1: Recall electric - potential formula
The formula for electric potential $V$ is $V=\frac{U}{q}$, where $U$ is the electric - potential energy and $q$ is the charge.
Step2: Substitute given values
Given $U = 1.08\times10^{-2}\text{ J}$ and $q=7.2\times 10^{-5}\text{ C}$. Then $V=\frac{1.08\times 10^{-2}}{7.2\times 10^{-5}}$.
Step3: Simplify the expression
Using the rule of exponents $\frac{a^m}{a^n}=a^{m - n}$, we have $V=\frac{1.08}{7.2}\times10^{-2+5}$. $\frac{1.08}{7.2}=0.15$, and $10^{-2 + 5}=10^{3}$. So $V = 0.15\times10^{3}=150\text{ V}$.
Answer:
150