10. what is the kinetic energy of a 2025.7 kg car that travels at 23.2 m/s?

Answer:

5.43×10⁵ J (or 543000 J approximately)

Explanation:

Step1: Recall the kinetic energy formula

The formula for kinetic energy (KE) is $KE = \frac{1}{2}mv^2$, where $m$ is the mass of the object and $v$ is its velocity.

Step2: Identify the given values

Here, the mass $m = 2025.7\space kg$ and the velocity $v = 23.2\space m/s$.

Step3: Substitute the values into the formula

First, calculate $v^2$: $v^2=(23.2)^2 = 23.2\times23.2 = 538.24$. Then, calculate $\frac{1}{2}m$: $\frac{1}{2}\times2025.7 = 1012.85$. Now, multiply these two results: $KE = 1012.85\times538.24$.

Step4: Perform the multiplication

$1012.85\times538.24 = 1012.85\times(500 + 38.24)=1012.85\times500+1012.85\times38.24 = 506425+38731.384 = 545156.384\space J$. Rounding to a reasonable number of significant figures (the given values have three significant figures in velocity and four in mass, so we can present it as approximately $5.43\times10^5\space J$ or 543000 J).