11. a 40 kg cart is pushed with a 200 n force. if friction is 40 n, what is the acceleration?\n12. a 20 kg…

11. a 40 kg cart is pushed with a 200 n force. if friction is 40 n, what is the acceleration?\n12. a 20 kg box is pulled with 60 n, but friction opposes motion with 20 n. find the acceleration.\n13. a 2,000 kg truck accelerates at 1.5 m/s². what net force acts on the truck?\n14. a 0.25 kg baseball is hit with a force of 20 n. what acceleration does it experience?\n15. a 70 kg skateboarder accelerates down a hill at 1.2 m/s². find the net force acting on the skateboarder.\n16. a 3 kg cart is pushed by a 20 n force while friction is 2 n. determine its acceleration.

11. a 40 kg cart is pushed with a 200 n force. if friction is 40 n, what is the acceleration?\n12. a 20 kg box is pulled with 60 n, but friction opposes motion with 20 n. find the acceleration.\n13. a 2,000 kg truck accelerates at 1.5 m/s². what net force acts on the truck?\n14. a 0.25 kg baseball is hit with a force of 20 n. what acceleration does it experience?\n15. a 70 kg skateboarder accelerates down a hill at 1.2 m/s². find the net force acting on the skateboarder.\n16. a 3 kg cart is pushed by a 20 n force while friction is 2 n. determine its acceleration.

Answer

Explanation:

Step1: Calculate net force

According to Newton's second law (F = ma), first find the net force (F_{net}). For the problem of the cart ((m = 40\space kg), (F_{applied}=200\space N), (F_{friction} = 40\space N)), (F_{net}=F_{applied}-F_{friction}). (F_{net}=200 - 40=160\space N)

Step2: Calculate acceleration

Use the formula (a=\frac{F_{net}}{m}). Substitute (F_{net} = 160\space N) and (m = 40\space kg) into the formula. (a=\frac{160}{40}=4\space m/s^{2})

Answer:

(4\space m/s^{2})