12. change the simulation to make the collision inelastic by sliding the bar all the way to the left…

12. change the simulation to make the collision inelastic by sliding the bar all the way to the left. (elasticity = 0%) 13. change the masses and velocities back to the original values and fill out the table. (2 pts) \n| |mass|velocity before the collision| momentum before the collision|velocity after the collision|momentum after the collision|\n|--|--|--|--|--|--|\n|ball 1 (blue)|0.5 kg|1.00 m/s|0.50 kg·m/s| | |\n|ball 2 (pink)|1.5 kg|-0.5 m/s|-0.75 kg·m/s| | |\n|total| | | | |\nmomentum:

12. change the simulation to make the collision inelastic by sliding the bar all the way to the left. (elasticity = 0%) 13. change the masses and velocities back to the original values and fill out the table. (2 pts) \n| |mass|velocity before the collision| momentum before the collision|velocity after the collision|momentum after the collision|\n|--|--|--|--|--|--|\n|ball 1 (blue)|0.5 kg|1.00 m/s|0.50 kg·m/s| | |\n|ball 2 (pink)|1.5 kg|-0.5 m/s|-0.75 kg·m/s| | |\n|total| | | | |\nmomentum:

Answer

Explanation:

Step1: Recall conservation of momentum for in - elastic collision

In an in - elastic collision, the two objects stick together after the collision. The total momentum before the collision is equal to the total momentum after the collision. The formula for momentum is $p = mv$. The total momentum before the collision $p_{total - before}=p_1 + p_2$, where $p_1=m_1v_1$ and $p_2=m_2v_2$. Here, $m_1 = 0.5$ kg, $v_1=1.00$ m/s, $m_2 = 1.5$ kg, $v_2=- 0.5$ m/s. $p_1=m_1v_1=0.5\times1.00 = 0.50$ kg·m/s and $p_2=m_2v_2=1.5\times(-0.5)=-0.75$ kg·m/s. So, $p_{total - before}=0.50+( - 0.75)=-0.25$ kg·m/s.

Step2: Calculate velocity after collision

After the in - elastic collision, the two balls stick together, so the total mass $m_{total}=m_1 + m_2=0.5 + 1.5=2.0$ kg. Using the conservation of momentum $p_{total - before}=p_{total - after}$, and since $p_{total - after}=m_{total}v_{after}$, we can solve for $v_{after}$. $v_{after}=\frac{p_{total - before}}{m_{total}}=\frac{-0.25}{2.0}=-0.125$ m/s.

Step3: Calculate momentum after collision for each ball

Since they stick together, for ball 1 after the collision, $p_{1 - after}=m_1v_{after}=0.5\times(-0.125)=-0.0625$ kg·m/s. For ball 2 after the collision, $p_{2 - after}=m_2v_{after}=1.5\times(-0.125)=-0.1875$ kg·m/s.

Mass Velocity BEFORE the collision Momentum BEFORE the collision Velocity AFTER the collision Momentum AFTER the collision
Ball 1 (blue) 0.5 kg 1.00 m/s 0.50 kg·m/s - 0.125 m/s - 0.0625 kg·m/s
Ball 2 (pink) 1.5 kg - 0.5 m/s - 0.75 kg·m/s - 0.125 m/s - 0.1875 kg·m/s
Total Momentum: - 0.25 kg·m/s - 0.25 kg·m/s

Answer:

Mass Velocity BEFORE the collision Momentum BEFORE the collision Velocity AFTER the collision Momentum AFTER the collision
Ball 1 (blue) 0.5 kg 1.00 m/s 0.50 kg·m/s - 0.125 m/s - 0.0625 kg·m/s
Ball 2 (pink) 1.5 kg - 0.5 m/s - 0.75 kg·m/s - 0.125 m/s - 0.1875 kg·m/s
Total Momentum: - 0.25 kg·m/s - 0.25 kg·m/s