a 120 ohm resistor is connected in series with a 180 ohm resistor, and attached to a battery. the voltage…

a 120 ohm resistor is connected in series with a 180 ohm resistor, and attached to a battery. the voltage drop across the 120 ohm resistor is 6.00 v. what is the voltage drop across the 180 ohm resistor? (hint: how much current is flowing?) (unit = v)

a 120 ohm resistor is connected in series with a 180 ohm resistor, and attached to a battery. the voltage drop across the 120 ohm resistor is 6.00 v. what is the voltage drop across the 180 ohm resistor? (hint: how much current is flowing?) (unit = v)

Answer

Explanation:

Step1: Calculate the current in the circuit

In a series - circuit, the current through each resistor is the same. Using Ohm's law $I=\frac{V}{R}$, for the 120 - Ohm resistor, where $V = 6.00$ V and $R = 120$ $\Omega$. So, $I=\frac{V_1}{R_1}$, and $I=\frac{6.00}{120}=0.05$ A.

Step2: Calculate the voltage drop across the 180 - Ohm resistor

Again, using Ohm's law $V = IR$. Here, $I = 0.05$ A (the current calculated in Step 1) and $R = 180$ $\Omega$. So, $V_2=I\times R_2=0.05\times180 = 9.00$ V.

Answer:

9.00 V