13 an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 m/s. after 5.00 s, the…

13 an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 m/s. after 5.00 s, the velocity is 51.0 m/s upward. at what rate is the arrow decelerated? multiple choice a = 9.80 m/s² a = -4.9 m/s² a = -9.80 m/s² a = 20.0 m/s²
Answer
Explanation:
Step1: Recall acceleration formula
The formula for acceleration is $a=\frac{v - u}{t}$, where $v$ is final - velocity, $u$ is initial - velocity, and $t$ is time.
Step2: Identify given values
$u = 100.0\ m/s$, $v = 51.0\ m/s$, $t = 5.00\ s$.
Step3: Substitute values into formula
$a=\frac{51.0 - 100.0}{5.00}=\frac{- 49.0}{5.00}=-9.80\ m/s^{2}$
Answer:
$a=-9.80\ m/s^{2}$ (corresponding to the third option in the multiple - choice list)