14. the momentum of a truck traveling in a straight line at 25 m/s is 37,500 kg m/s. what is the trucks…
14. the momentum of a truck traveling in a straight line at 25 m/s is 37,500 kg m/s. what is the trucks mass?\na) 1,500 kg\nb) 1,500 n\nc) 937,500 n\nd) 937,500 kg\n15. which object listed below has the greatest momentum?\na) a 0.4 kg object rolling at 2 m/s.\nb) a 0.05 kg object rolling at 0.2 m/s.\nc) a 0.15 kg object rolling at 1 m/s.\nd) a 0.15 kg object rolling at 2 m/s.\n16. the definition of momentum is\na) the size of an object\nb) the velocity of an object\nc) mass in motion\nd) a comparison between two objects\n17. what is the objects momentum for 8 m/s\na) 12\nb) 8\nc) 10\nd) 6\n18. travel by car according to this graph, between 0.75 hours and 1.25 hours, what was occurring?\na) the object was stopped.\nb) the object was traveling at a constant speed.\nc) the object was traveling at an average speed.\nd) the object was traveling at an accelerated speed.
Answer
14.
Explanation:
Step1: Recall momentum formula
The formula for momentum is $p = mv$, where $p$ is momentum, $m$ is mass and $v$ is velocity. We need to solve for $m$, so $m=\frac{p}{v}$.
Step2: Substitute values
Given $p = 37500\ kg\cdot m/s$ and $v = 25\ m/s$. Then $m=\frac{37500}{25}=1500\ kg$.
Answer:
a) 1,500 kg
15.
Explanation:
Step1: Calculate momentum for each option
For option a), $p_a=m_av_a = 0.4\times2=0.8\ kg\cdot m/s$. For option b), $p_b=m_bv_b=0.05\times0.2 = 0.01\ kg\cdot m/s$. For option c), $p_c=m_cv_c=0.15\times1 = 0.15\ kg\cdot m/s$. For option d), $p_d=m_dv_d=0.15\times2=0.3\ kg\cdot m/s$.
Step2: Compare values
Comparing $p_a = 0.8\ kg\cdot m/s$, $p_b=0.01\ kg\cdot m/s$, $p_c = 0.15\ kg\cdot m/s$ and $p_d=0.3\ kg\cdot m/s$, we see that option a) has the greatest momentum.
Answer:
a) A 0.4 kg object rolling at 2 m/s
16.
Brief Explanations:
Momentum is defined as the product of an object's mass and its velocity, which can be thought of as mass in motion.
Answer:
c) Mass in Motion
17.
Explanation:
Step1: Determine the relationship from the graph
The graph shows a linear relationship between momentum and velocity. If we assume the relationship is $p = mv$, and we can find the mass from the slope of the line (since $m=\frac{p}{v}$). From the graph, when $v = 2\ m/s$, $p= 2.0\ kg\cdot m/s$, so $m = 1\ kg$.
Step2: Calculate momentum at 8 m/s
Using $p=mv$ with $m = 1\ kg$ and $v = 8\ m/s$, we get $p=8\ kg\cdot m/s$.
Answer:
b) 8
18.
Brief Explanations:
On a distance - time graph, a horizontal line indicates that the distance is not changing with time, which means the object is stopped.
Answer:
a) The object was stopped.