a 0.155 kg arrow is shot upward at 31.4 m/s. what is the potential energy of the arrow the moment it leaves…

a 0.155 kg arrow is shot upward at 31.4 m/s. what is the potential energy of the arrow the moment it leaves the bow? pe = ? j

a 0.155 kg arrow is shot upward at 31.4 m/s. what is the potential energy of the arrow the moment it leaves the bow? pe = ? j

Answer

Explanation:

Step1: Recall potential - energy formula

At the moment the arrow leaves the bow, its height $h = 0$. The formula for gravitational potential energy is $PE=mgh$, where $m$ is mass, $g$ is the acceleration due to gravity ($g = 9.8\ m/s^{2}$), and $h$ is height.

Step2: Substitute values

Since $h = 0$ at the moment of leaving the bow, $PE=0.155\times9.8\times0$.

Answer:

$0$