a 155 g unknown metal was heated from 25°c to 40°c. if it absorbed 551.0 joules of energy in the process…

Explanation:

Step1: Identify the formula

The formula for heat absorbed is $Q = mc\Delta T$, where $Q$ is the heat absorbed, $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature. We need to solve for $c$, so we can re - arrange the formula to $c=\frac{Q}{m\Delta T}$.

Step2: Calculate the change in temperature

$\Delta T=T_{2}-T_{1}=40^{\circ}C - 25^{\circ}C=15^{\circ}C$.

Step3: Substitute the values into the formula

We know that $Q = 551.0\ J$, $m = 155\ g$, and $\Delta T=15^{\circ}C$. Substituting these values into $c=\frac{Q}{m\Delta T}$, we get $c=\frac{551.0\ J}{155\ g\times15^{\circ}C}$.

Step4: Calculate the specific heat

$c=\frac{551.0}{155\times15}\ J/(g\cdot^{\circ}C)=\frac{551.0}{2325}\ J/(g\cdot^{\circ}C)\approx0.237\ J/(g\cdot^{\circ}C)$.

Answer:

$0.237\ J/(g\cdot^{\circ}C)$