5) if i have 17 moles of gas at a temperature of 67 °c, and a volume of 88.89 liters, what is the pressure…

Explanation:

Step1: Convert temperature to Kelvin

$T = 67^{\circ}C+273.15 = 340.15\ K$

Step2: Use the ideal - gas law

The ideal - gas law is $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal - gas constant ($R=0.0821\ L\cdot atm/(mol\cdot K)$), and $T$ is temperature. We want to solve for $P$, so $P=\frac{nRT}{V}$. Substitute $n = 17\ mol$, $R = 0.0821\ L\cdot atm/(mol\cdot K)$, $T = 340.15\ K$, and $V = 88.89\ L$ into the formula. $P=\frac{17\ mol\times0.0821\ L\cdot atm/(mol\cdot K)\times340.15\ K}{88.89\ L}$

Step3: Calculate the pressure

$P=\frac{17\times0.0821\times340.15}{88.89}\ atm$ $P=\frac{476.97}{88.89}\ atm\approx5.37\ atm$

Answer:

$5.37\ atm$