a 23.7 kg child initially sitting at rest slides down a frictionless water slide that is inclined at 27.2°…

a 23.7 kg child initially sitting at rest slides down a frictionless water slide that is inclined at 27.2°. if the slide is 5.75 m long, what is the childs velocity when reaching the bottom of the slide? a = 4.48 m/s² v_f = ? m/s

a 23.7 kg child initially sitting at rest slides down a frictionless water slide that is inclined at 27.2°. if the slide is 5.75 m long, what is the childs velocity when reaching the bottom of the slide? a = 4.48 m/s² v_f = ? m/s

Answer

Explanation:

Step1: Identify the kinematic - equation

We use the kinematic equation $v_f^2=v_i^2 + 2ax$. Since the child starts from rest, $v_i = 0$.

Step2: Substitute the values

We know that $a = 4.48\ m/s^2$ and $x=5.75\ m$, and $v_i = 0$. Substituting into the equation $v_f^2=v_i^2 + 2ax$, we get $v_f^2=0 + 2\times4.48\times5.75$.

Step3: Calculate $v_f$

First, calculate $2\times4.48\times5.75=2\times25.76 = 51.52$. Then, $v_f=\sqrt{51.52}\approx7.18\ m/s$.

Answer:

$7.18$