24. how much energy is released by 650g of water as it cools from its boiling point to its freezing point…
24. how much energy is released by 650g of water as it cools from its boiling point to its freezing point? the specific heat capacity of water is 4.18 j/g°c. enter your answer in the box provided. record your answer to the nearest kilojoules. kilojoules
Answer
Explanation:
Step1: Identify temperature - change
The boiling point of water is $100^{\circ}C$ and the freezing point is $0^{\circ}C$. So, $\Delta T=100 - 0=100^{\circ}C$.
Step2: Use the heat - transfer formula
The formula for heat transfer is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. Given $m = 650g$, $c=4.18J/g^{\circ}C$, and $\Delta T = 100^{\circ}C$. Then $Q=650\times4.18\times100$. $Q = 650\times418=271700J$.
Step3: Convert to kilojoules
Since $1kJ = 1000J$, then $Q=\frac{271700}{1000}=271.7kJ$. Rounding to the nearest kilojoule, $Q\approx272kJ$.
Answer:
272