a 0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 n. what impulse is…

a 0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 n. what impulse is delivered to the ball?\n33 kg·\\frac{m}{s}\n140 kg·\\frac{m}{s}\n4600 kg·\\frac{m}{s}\n74,000 kg·\\frac{m}{s}

a 0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 n. what impulse is delivered to the ball?\n33 kg·\\frac{m}{s}\n140 kg·\\frac{m}{s}\n4600 kg·\\frac{m}{s}\n74,000 kg·\\frac{m}{s}

Answer

Explanation:

Step1: Recall impulse - force formula

The formula for impulse $J$ is $J = F\Delta t$, where $F$ is the force and $\Delta t$ is the time - interval.

Step2: Identify given values

We are given that $F = 18500\ N$ and $\Delta t=0.0075\ s$.

Step3: Calculate the impulse

Substitute the values into the formula: $J = 18500\times0.0075$. $J = 138.75\ kg\cdot\frac{m}{s}\approx140\ kg\cdot\frac{m}{s}$

Answer:

$140\ kg\cdot\frac{m}{s}$