28.5 g of iron shot is added to a graduated cylinder containing 45.50 ml of water. the water level rises to…

28.5 g of iron shot is added to a graduated cylinder containing 45.50 ml of water. the water level rises to the 49.10 ml mark, from this information, calculate the density of iron.

28.5 g of iron shot is added to a graduated cylinder containing 45.50 ml of water. the water level rises to the 49.10 ml mark, from this information, calculate the density of iron.

Answer

Explanation:

Step1: Calculate the volume of iron shot

The volume of iron shot is equal to the change in water - level in the graduated cylinder. $V = 49.10\ mL - 45.50\ mL=3.60\ mL$ Since $1\ mL = 1\ cm^{3}$, $V = 3.60\ cm^{3}$

Step2: Calculate the density of iron shot

The density formula is $\rho=\frac{m}{V}$, where $m = 28.5\ g$ and $V = 3.60\ cm^{3}$ $\rho=\frac{28.5\ g}{3.60\ cm^{3}}\approx7.92\ g/cm^{3}$

Answer:

$7.92\ g/cm^{3}$