2.38 c of charge move between the terminals of a battery with a potential difference of 9.00 v. how much…
2.38 c of charge move between the terminals of a battery with a potential difference of 9.00 v. how much energy does it gain? (unit = j)
Answer
Explanation:
Step1: Recall the formula
The formula for electrical energy $W$ is $W = qV$, where $q$ is the charge and $V$ is the potential - difference.
Step2: Substitute the values
Given $q = 2.38\ C$ and $V=9.00\ V$. Substitute these values into the formula: $W=(2.38\ C)\times(9.00\ V)$.
Step3: Calculate the energy
$W = 2.38\times9.00\ J=21.42\ J$.
Answer:
$21.42$