2. a 0.50 - kilogram object moves in a horizontal circular path with a radius of 0.25 meter at a constant…

2. a 0.50 - kilogram object moves in a horizontal circular path with a radius of 0.25 meter at a constant speed of 4.0 meters per second. what is the magnitude of the objects acceleration? 8 m/s² 16 m/s² 32 m/s² 64 m/s² clear all

2. a 0.50 - kilogram object moves in a horizontal circular path with a radius of 0.25 meter at a constant speed of 4.0 meters per second. what is the magnitude of the objects acceleration? 8 m/s² 16 m/s² 32 m/s² 64 m/s² clear all

Answer

Explanation:

Step1: Identify centripetal - acceleration formula

The formula for centripetal acceleration is $a = \frac{v^{2}}{r}$, where $v$ is the speed and $r$ is the radius.

Step2: Substitute given values

Given $v = 4.0\ m/s$ and $r=0.25\ m$. Substitute into the formula: $a=\frac{(4.0)^{2}}{0.25}$.

Step3: Calculate the acceleration

$(4.0)^{2}=16$, and $\frac{16}{0.25}=64\ m/s^{2}$.

Answer:

$64\ m/s^{2}$