50 word problems — pe, ke, work, and power (v3)\nname: matthew franks date: class: 2nd period\nsolve each…

50 word problems — pe, ke, work, and power (v3)\nname: matthew franks date: class: 2nd period\nsolve each. show units. use g = 9.8 m/s² unless stated.\n1) an object has ke = 800 j while v = 8.0 m/s. find m.\n2) a pump does w = 45000 j in t = 90 s. find p.\n3) a 65 kg skateboarder moves at v = 4.5 m/s. find ke.\n4) a 25 kg suitcase rests 1.2 m above the floor. find pe.\n5) a 0.50 kg puck slides at v = 0.8 m/s. find ke.\n6) a treadmill shows w = 9600 j in t = 80 s. find p.\n7) a 0.15 kg baseball is thrown at v = 20 m/s. find ke.\n8) a drill uses p = 300 w to do w = 600 j. find t.\n9) a robot arm applies f = 42 n over d = 0.50 m. find w.\n10) a 0.20 kg arrow leaves at v = 45 m/s. find ke.\n11) a toy car has ke = 1000 j at v = 10 m/s. find m.\n12) a box has pe = 980 j at height h = 10.0 m. find m.\n13) a blender outputs p = 280 w and performs w = 2000 j. find t.\n14) a pump runs at p = 800 w to do w = 12800 j. find t.\n15) a sled has ke = 720 j at v = 12 m/s. find m.\n16) a crane cable pulls with f = 1200 n for d = 1.5 m. find w.\n17) a hoist does w = 8000 j in t = 20 s. find p.\n18) a winch expends w = 25000 j in t = 50 s. find p.\n19) a 50 kg trunk has pe = 4900 j. find h.\n20) a mover pushes with f = 75 n for d = 4.0 m. find w.\n21) a 900 kg compact car cruises at v = 18 m/s. find ke.\n22) a package has pe = 1960 j at h = 4.0 m. find m.\n23) a 0.05 kg hammer sits on a 2.0 m shelf. find pe.\n24) a student does w = 180 j sliding a box d = 3.0 m. find f.\n25) a 7.0 kg shot has ke = 686 j. find v.\n26) a 12 kg backpack has pe = 706 j. find h.\n27) a 15 kg box has pe = 1470 j. find h.\n28) a student pushes with f = 35 n over d = 6.0 m. find w (work).\n29) a tugboat does w = 3600 j pulling d = 12 m. find f.\n30) a worker does w = 1350 j over d = 9.0 m. find f.\n31) a 12 kg backpack is lifted 2.2 m. find pe.\n32) a 18 kg box is raised to 1.8 m. find pe.\n33) a gardener exerts f = 90 n across d = 7.0 m. find w.\n34) a 5.0 kg mass has ke = 450 j. find v.\n35) a worker does w = 2500 j pushing d = 25 m. find f.

50 word problems — pe, ke, work, and power (v3)\nname: matthew franks date: class: 2nd period\nsolve each. show units. use g = 9.8 m/s² unless stated.\n1) an object has ke = 800 j while v = 8.0 m/s. find m.\n2) a pump does w = 45000 j in t = 90 s. find p.\n3) a 65 kg skateboarder moves at v = 4.5 m/s. find ke.\n4) a 25 kg suitcase rests 1.2 m above the floor. find pe.\n5) a 0.50 kg puck slides at v = 0.8 m/s. find ke.\n6) a treadmill shows w = 9600 j in t = 80 s. find p.\n7) a 0.15 kg baseball is thrown at v = 20 m/s. find ke.\n8) a drill uses p = 300 w to do w = 600 j. find t.\n9) a robot arm applies f = 42 n over d = 0.50 m. find w.\n10) a 0.20 kg arrow leaves at v = 45 m/s. find ke.\n11) a toy car has ke = 1000 j at v = 10 m/s. find m.\n12) a box has pe = 980 j at height h = 10.0 m. find m.\n13) a blender outputs p = 280 w and performs w = 2000 j. find t.\n14) a pump runs at p = 800 w to do w = 12800 j. find t.\n15) a sled has ke = 720 j at v = 12 m/s. find m.\n16) a crane cable pulls with f = 1200 n for d = 1.5 m. find w.\n17) a hoist does w = 8000 j in t = 20 s. find p.\n18) a winch expends w = 25000 j in t = 50 s. find p.\n19) a 50 kg trunk has pe = 4900 j. find h.\n20) a mover pushes with f = 75 n for d = 4.0 m. find w.\n21) a 900 kg compact car cruises at v = 18 m/s. find ke.\n22) a package has pe = 1960 j at h = 4.0 m. find m.\n23) a 0.05 kg hammer sits on a 2.0 m shelf. find pe.\n24) a student does w = 180 j sliding a box d = 3.0 m. find f.\n25) a 7.0 kg shot has ke = 686 j. find v.\n26) a 12 kg backpack has pe = 706 j. find h.\n27) a 15 kg box has pe = 1470 j. find h.\n28) a student pushes with f = 35 n over d = 6.0 m. find w (work).\n29) a tugboat does w = 3600 j pulling d = 12 m. find f.\n30) a worker does w = 1350 j over d = 9.0 m. find f.\n31) a 12 kg backpack is lifted 2.2 m. find pe.\n32) a 18 kg box is raised to 1.8 m. find pe.\n33) a gardener exerts f = 90 n across d = 7.0 m. find w.\n34) a 5.0 kg mass has ke = 450 j. find v.\n35) a worker does w = 2500 j pushing d = 25 m. find f.

Answer

  1. Problem 11: A toy car has (KE = 1000\ J) at (v=10\ m/s). Find (m).

Explanation:

Step1: Recall the kinetic - energy formula

The formula for kinetic energy is (KE=\frac{1}{2}mv^{2}). We need to solve for (m). [KE = \frac{1}{2}mv^{2}]

Step2: Rearrange the formula for (m)

[m=\frac{2KE}{v^{2}}]

Step3: Substitute the given values

Substitute (KE = 1000\ J) and (v = 10\ m/s) into the formula. [m=\frac{2\times1000}{10^{2}}=\frac{2000}{100}=20\ kg]

Answer:

(20\ kg)

  1. Problem 12: A box has (PE = 980\ J) at height (h = 10.0\ m). Find (m).

Explanation:

Step1: Recall the potential - energy formula

The formula for gravitational potential energy is (PE=mgh), where (g = 9.8\ m/s^{2}). We need to solve for (m). [PE=mgh]

Step2: Rearrange the formula for (m)

[m=\frac{PE}{gh}]

Step3: Substitute the given values

Substitute (PE = 980\ J), (g = 9.8\ m/s^{2}), and (h = 10.0\ m) into the formula. [m=\frac{980}{9.8\times10}=\frac{980}{98}=10\ kg]

Answer:

(10\ kg)

  1. Problem 16: A crane cable pulls with (F = 1200\ N) for (d = 1.5\ m). Find (W).

Explanation:

Step1: Recall the work - formula

The formula for work is (W = Fd), where (F) is the force and (d) is the displacement in the direction of the force. [W=Fd]

Step2: Substitute the given values

Substitute (F = 1200\ N) and (d = 1.5\ m) into the formula. [W=1200\times1.5 = 1800\ J]

Answer:

(1800\ J)

  1. Problem 17: A hoist does (W = 8000\ J) in (t = 20\ s). Find (P).

Explanation:

Step1: Recall the power formula

The formula for power is (P=\frac{W}{t}), where (W) is the work done and (t) is the time taken. [P=\frac{W}{t}]

Step2: Substitute the given values

Substitute (W = 8000\ J) and (t = 20\ s) into the formula. [P=\frac{8000}{20}=400\ W]

Answer:

(400\ W)

  1. Problem 24: A student does (W = 180\ J) sliding a box (d = 3.0\ m). Find (F).

Explanation:

Step1: Recall the work formula

The formula for work is (W = Fd). We need to solve for (F). [W=Fd]

Step2: Rearrange the formula for (F)

[F=\frac{W}{d}]

Step3: Substitute the given values

Substitute (W = 180\ J) and (d = 3.0\ m) into the formula. [F=\frac{180}{3}=60\ N]

Answer:

(60\ N)