a 60.0 kg runner is moving at 6.00 m/s and speeds up to 9.00 m/s. the runners change in kinetic energy is…

a 60.0 kg runner is moving at 6.00 m/s and speeds up to 9.00 m/s. the runners change in kinetic energy is 1,350 j. how much work was done?\n-2,430 j\n-1,350 j\n1,350 j\n2,430 j

a 60.0 kg runner is moving at 6.00 m/s and speeds up to 9.00 m/s. the runners change in kinetic energy is 1,350 j. how much work was done?\n-2,430 j\n-1,350 j\n1,350 j\n2,430 j

Answer

Answer:

C. 1,350 J

Explanation:

Step1: Recall work - energy theorem

The work - energy theorem states that the net work done on an object is equal to its change in kinetic energy, $W=\Delta K$.

Step2: Identify given values

We are given that the change in kinetic energy $\Delta K = 1350\ J$.

Step3: Determine work done

According to the work - energy theorem, since $W = \Delta K$, the work done $W=1350\ J$.