a 600 kg car is at rest, and then accelerates to 5 m/s. what is its original kinetic energy? j what is its…

Answer:

1. 0
2. 7500
3. 7500

Explanation:

Step1: Recall kinetic - energy formula

The formula for kinetic energy is $K = \frac{1}{2}mv^{2}$, where $m$ is the mass and $v$ is the velocity.

Step2: Calculate original kinetic energy

The car is at rest initially, so $v_1 = 0\ m/s$ and $m = 600\ kg$. Substitute into the formula: $K_1=\frac{1}{2}\times600\times0^{2}=0\ J$.

Step3: Calculate final kinetic energy

The final velocity $v_2 = 5\ m/s$ and $m = 600\ kg$. Substitute into the formula: $K_2=\frac{1}{2}\times600\times5^{2}=\frac{1}{2}\times600\times25 = 7500\ J$.

Step4: Use work - energy theorem

According to the work - energy theorem, the work done $W$ on an object is equal to the change in its kinetic energy, $W=\Delta K=K_2 - K_1$. Since $K_1 = 0\ J$ and $K_2 = 7500\ J$, then $W=7500 - 0=7500\ J$.