a 75.0 w bulb is connected to a 110 v (dc) outlet. what is the resistance of the bulb? (unit = ohms)

Explanation:

Step1: Recall power - voltage - resistance formula

The power formula is $P=\frac{V^{2}}{R}$, where $P$ is power, $V$ is voltage and $R$ is resistance. We need to solve for $R$.

Step2: Rearrange the formula for $R$

From $P = \frac{V^{2}}{R}$, we can get $R=\frac{V^{2}}{P}$.

Step3: Substitute given values

Given $V = 110\ V$ and $P=75.0\ W$. Substitute into the formula: $R=\frac{(110)^{2}}{75.0}=\frac{12100}{75.0}$.

Step4: Calculate the value of $R$

$R=\frac{12100}{75.0}\approx161.33\ \Omega$.

Answer:

$161.33$