80 - kg person sits 3.0 m from the center of a horizontally rotating platform with a tangential speed of 4.0…
80 - kg person sits 3.0 m from the center of a horizontally rotating platform with a tangential speed of 4.0 m/s. what is the angular momentum of the person? express your answer in kilograms - meters squared per second. l = kg·m²/s
Answer
Explanation:
Step1: Recall angular - momentum formula
The formula for angular momentum is $L = mvr$, where $m$ is the mass, $v$ is the tangential speed, and $r$ is the distance from the axis of rotation.
Step2: Identify given values
Given $m = 80\ kg$, $v=4.0\ m/s$, and $r = 3.0\ m$.
Step3: Substitute values into formula
$L=(80\ kg)\times(4.0\ m/s)\times(3.0\ m)$ $L = 960\ kg\cdot m^{2}/s$
Answer:
$960$