adam takes a bus on a school field - trip. the bus route is split into the five legs listed in the table…

adam takes a bus on a school field - trip. the bus route is split into the five legs listed in the table. find the average velocity for each leg of the trip. then arrange the legs of the trip from highest velocity to lowest.\n| leg | distance (km) | time (min) |\n| ---- | ---- | ---- |\n| a | 18 | 9 |\n| b | 25 | 15 |\n| c | 24 | 8 |\n| d | 48 | 12 |\n| e | 15 | 7 |
Answer
Answer:
D, C, E, A, B
Explanation:
Step1: Calculate velocity for each leg
Velocity = Distance/Time. Leg A: $18/9 = 2$ km/min; Leg B: $25/15 ≈ 1.67$ km/min; Leg C: $24/8 = 3$ km/min; Leg D: $48/12 = 4$ km/min; Leg E: $15/7 ≈ 2.14$ km/min.
Step2: Order velocities from highest to lowest
4 (D) > 3 (C) > 2.14 (E) > 2 (A) > 1.67 (B).