an adult eagle and an eagle chick are in a nest that is 30 meters (m) above ground level. the adult eagle…

an adult eagle and an eagle chick are in a nest that is 30 meters (m) above ground level. the adult eagle has a mass of 5.5 kilograms (kg), and the eagle chick has a mass of 1.2 kg. which statement describes the gravitational relationship between the eagles and earth?\na neither eagle exerts a gravitational force on earth.\nb the adult eagle exerts a greater gravitational force on earth than the eagle chick does.\nc earth exerts a greater gravitational force on the eagle chick than it does on the adult eagle.\nd the difference in the masses of the adult eagle and the eagle chick does not affect their gravitational force on earth.

an adult eagle and an eagle chick are in a nest that is 30 meters (m) above ground level. the adult eagle has a mass of 5.5 kilograms (kg), and the eagle chick has a mass of 1.2 kg. which statement describes the gravitational relationship between the eagles and earth?\na neither eagle exerts a gravitational force on earth.\nb the adult eagle exerts a greater gravitational force on earth than the eagle chick does.\nc earth exerts a greater gravitational force on the eagle chick than it does on the adult eagle.\nd the difference in the masses of the adult eagle and the eagle chick does not affect their gravitational force on earth.

Answer

Explanation:

Step1: Recall gravitational - force formula

The gravitational force between two objects is given by $F = G\frac{Mm}{r^{2}}$, where $G$ is the gravitational constant, $M$ is the mass of the Earth, $m$ is the mass of the object, and $r$ is the distance between the center of the Earth and the object. Since $G$, $M$, and $r$ are the same for both eagles (they are at the same height above the Earth), the gravitational force $F$ is directly proportional to the mass $m$ of the object.

Step2: Compare masses of eagles

The adult eagle has a mass $m_1=5.5$ kg and the eagle - chick has a mass $m_2 = 1.2$ kg. Since $m_1>m_2$, according to the formula $F = G\frac{Mm}{r^{2}}$, the gravitational force exerted by the adult eagle on the Earth (and vice - versa) is greater than the gravitational force exerted by the eagle chick on the Earth.

Answer:

B. The adult eagle exerts a greater gravitational force on Earth than the eagle chick does.