always use significant figure rules. remember that these rules apply to all numbers that are measurements. a…

always use significant figure rules. remember that these rules apply to all numbers that are measurements. a train starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s². how far does the train travel in this time interval?\n20\n19\n7.5
Answer
Explanation:
Step1: Identificar la ecuación
Usamos la ecuación $x = v_0t+\frac{1}{2}at^{2}$, donde $v_0 = 0$ (arranca del reposo).
Step2: Sustituir valores
Sustituimos $v_0 = 0$, $a = 1.5\ m/s^{2}$ y $t = 5.0\ s$ en la ecuación. Dado que $v_0 = 0$, la ecuación se reduce a $x=\frac{1}{2}at^{2}$. Entonces $x=\frac{1}{2}\times1.5\times(5.0)^{2}$.
Step3: Realizar cálculo
$x=\frac{1}{2}\times1.5\times25 = 18.75\ m$.
Step4: Aplicar reglas de cifras significativas
Dado que los datos de entrada ($5.0\ s$ y $1.5\ m/s^{2}$) tienen dos cifras significativas, redondeamos $18.75\ m$ a dos cifras significativas, obteniendo $19\ m$.
Answer:
$19$