the amount of potential energy, $p$, an object has is equal to the product of its mass, $m$, its height off…

the amount of potential energy, $p$, an object has is equal to the product of its mass, $m$, its height off the ground, $h$, and the gravitational constant, $g$. this can be modeled by the equation $p = mgh$. what is the equivalent equation solved for $h$? $\frac{(\frac{p}{m})}{g}=h$ $\frac{p}{mg}=h$ $pmg = h$ $\frac{p}{(\frac{m}{g})}=h$

the amount of potential energy, $p$, an object has is equal to the product of its mass, $m$, its height off the ground, $h$, and the gravitational constant, $g$. this can be modeled by the equation $p = mgh$. what is the equivalent equation solved for $h$? $\frac{(\frac{p}{m})}{g}=h$ $\frac{p}{mg}=h$ $pmg = h$ $\frac{p}{(\frac{m}{g})}=h$

Answer

Explanation:

Step1: Isolate h in the equation

Given $P = mgh$, divide both sides by $mg$. $\frac{P}{mg}=\frac{mgh}{mg}$

Step2: Simplify the right - hand side

$\frac{mgh}{mg}=h$, so $\frac{P}{mg}=h$

Answer:

$\frac{P}{mg}=h$ (the second option)