another temperature formula is $f = \\frac{9(k - 273.15)}{5}+32$, where f is degrees fahrenheit and k is…

another temperature formula is $f = \\frac{9(k - 273.15)}{5}+32$, where f is degrees fahrenheit and k is degrees kelvin. solve the temperature formula for k.\n$k = \\frac{5(f - 32)}{9}+273.15$\n$k = \\frac{9(f - 32)}{5}+273.15$\n$k = \\frac{5(f + 32)}{9}+273.15$\n$k = \\frac{5(f - 32)}{9}-273.15$

another temperature formula is $f = \\frac{9(k - 273.15)}{5}+32$, where f is degrees fahrenheit and k is degrees kelvin. solve the temperature formula for k.\n$k = \\frac{5(f - 32)}{9}+273.15$\n$k = \\frac{9(f - 32)}{5}+273.15$\n$k = \\frac{5(f + 32)}{9}+273.15$\n$k = \\frac{5(f - 32)}{9}-273.15$

Answer

Explanation:

Step1: Isolate the fraction term

Start with $F=\frac{9(K - 273.15)}{5}+32$. Subtract 32 from both sides: $F - 32=\frac{9(K - 273.15)}{5}$.

Step2: Eliminate the denominator

Multiply both sides by 5: $5(F - 32)=9(K - 273.15)$.

Step3: Solve for K

Divide both sides by 9: $\frac{5(F - 32)}{9}=K - 273.15$. Then add 273.15 to both sides: $K=\frac{5(F - 32)}{9}+273.15$.

Answer:

$K=\frac{5(F - 32)}{9}+273.15$ (corresponding to the first - option in the multiple - choice list)