answer the questions below about the trains.\n(a) what is the speed of each train?\ntrain a: 80…

answer the questions below about the trains.\n(a) what is the speed of each train?\ntrain a: 80 $\frac{m}{s}$\ntrain b: 65 $\frac{m}{s}$\ntrain c: 55 $\frac{m}{s}$\n(b) which train is the slowest?\ntrain a train b train c\n(c) how far does each train travel in 3 seconds?\ntrain a: meters\ntrain b: meters\ntrain c: meters

answer the questions below about the trains.\n(a) what is the speed of each train?\ntrain a: 80 $\frac{m}{s}$\ntrain b: 65 $\frac{m}{s}$\ntrain c: 55 $\frac{m}{s}$\n(b) which train is the slowest?\ntrain a train b train c\n(c) how far does each train travel in 3 seconds?\ntrain a: meters\ntrain b: meters\ntrain c: meters

Answer

Explanation:

Step1: Recall distance - speed formula

The formula for distance $d$ is $d = v\times t$, where $v$ is speed and $t$ is time.

Step2: Calculate distance for Train A

Given $v_A=80\frac{m}{s}$ and $t = 3s$. Using the formula $d_A=v_A\times t$, we have $d_A=80\times3 = 240$ meters.

Step3: Calculate distance for Train B

Given $v_B = 65\frac{m}{s}$ and $t = 3s$. Using the formula $d_B=v_B\times t$, we get $d_B=65\times3=195$ meters.

Step4: Calculate distance for Train C

Given $v_C = 55\frac{m}{s}$ and $t = 3s$. Using the formula $d_C=v_C\times t$, we obtain $d_C=55\times3 = 165$ meters.

Answer:

(a) Train A: $80\frac{m}{s}$, Train B: $65\frac{m}{s}$, Train C: $55\frac{m}{s}$ (b) Train C (c) Train A: 240 meters, Train B: 195 meters, Train C: 165 meters