an automobile tire at 30.0°c has a pressure of 3.00 atm. the temperature decreases to -5.00°c. assume that…

an automobile tire at 30.0°c has a pressure of 3.00 atm. the temperature decreases to -5.00°c. assume that there is no volume change in the tire. formula to use: $\frac{p_1}{t_1}=\frac{p_2}{t_2}$ how does the tire pressure change in response to the temperature change? decreases complete what is the new pressure of the tire after the temperature change? atm done
Answer
Answer:
2.70 atm
Explanation:
Step1: Convert temperatures to Kelvin
$T_1 = 30.0 + 273.15=303.15$ K, $T_2=- 5.00+273.15 = 268.15$ K
Step2: Rearrange the formula for $P_2$
Given $\frac{P_1}{T_1}=\frac{P_2}{T_2}$, then $P_2=\frac{P_1T_2}{T_1}$
Step3: Substitute values
$P_1 = 3.00$ atm, $T_1 = 303.15$ K, $T_2 = 268.15$ K. So $P_2=\frac{3.00\times268.15}{303.15}\approx2.70$ atm