what is the average kinetic energy of the electrons ejected based on the incident light and the work…

what is the average kinetic energy of the electrons ejected based on the incident light and the work function?\n$w_{pt} = 1.0 \\times 10^{-18}$ j\n$e_{i} = 1.59 \\times 10^{-18}$ j\n$ke = \\boldsymbol{?} \\times 10^{\\boldsymbol{?}}$ j

what is the average kinetic energy of the electrons ejected based on the incident light and the work function?\n$w_{pt} = 1.0 \\times 10^{-18}$ j\n$e_{i} = 1.59 \\times 10^{-18}$ j\n$ke = \\boldsymbol{?} \\times 10^{\\boldsymbol{?}}$ j

Answer

Explanation:

Step1: Recall photoelectric effect formula

The formula for the kinetic energy of ejected electrons is $KE = E_I - W_{Pt}$, where $E_I$ is the incident photon energy and $W_{Pt}$ is the work function.

Step2: Substitute given values

$KE = 1.59 \times 10^{-18}\ \text{J} - 1.0 \times 10^{-18}\ \text{J}$

Step3: Calculate the difference

$KE = 0.59 \times 10^{-18}\ \text{J}$

Step4: Adjust to standard form

Rewrite to match the required format: $KE = 5.9 \times 10^{-19}\ \text{J}$

Answer:

$KE = 5.9 \times 10^{-19}\ \text{J}$