6. an average net force caused an 11.0 kg object to accelerate uniformly from rest. if this object travels…

Explanation:

Step1: Find the acceleration

Use the kinematic equation (x = v_0t+\frac{1}{2}at^{2}). Since (v_0 = 0) (starts from rest), the equation simplifies to (x=\frac{1}{2}at^{2}). We can solve for (a): (a=\frac{2x}{t^{2}}) Substitute (x = 26.3\space m) and (t = 3.20\space s) (a=\frac{2\times26.3}{3.20^{2}}=\frac{52.6}{10.24}\approx5.14\space m/s^{2})

Step2: Find the final velocity

Use the kinematic equation (v = v_0+at). Since (v_0 = 0), (v=at) Substitute (a = 5.14\space m/s^{2}) and (t = 3.20\space s) (v=5.14\times3.20 = 16.45\space m/s)

Step3: Calculate the change in momentum

The initial momentum (p_i=mv_0 = 0) (since (v_0 = 0)). The final momentum (p_f=mv) The change in momentum (\Delta p=p_f - p_i=mv) Substitute (m = 11.0\space kg) and (v = 16.45\space m/s) (\Delta p=11.0\times16.45 = 181\space kg\cdot m/s) west

Answer:

(181\space kg\cdot m/s) west