2. a 2.0 l balloon containing nitrogen gas is cooled from 25.0 °c to 0.0 °c. what is the final volume of the…

Explanation:

Step1: Convert temperatures to Kelvin

$T_1 = 25.0 + 273.15=298.15\ K$ $T_2 = 0.0+ 273.15 = 273.15\ K$

Step2: Apply Charles's Law ($\frac{V_1}{T_1}=\frac{V_2}{T_2}$)

We know $V_1 = 2.0\ L$, $T_1 = 298.15\ K$, $T_2=273.15\ K$. Rearranging for $V_2$ gives $V_2=\frac{V_1T_2}{T_1}$. $V_2=\frac{2.0\ L\times273.15\ K}{298.15\ K}$

Step3: Calculate the final volume

$V_2=\frac{2.0\times273.15}{298.15}\ L\approx1.83\ L$

Answer:

$1.83\ L$