5. a balloon is filled with 35.0 l of helium in the morning when the temperature is 293. by noon the…

Explanation:

Step1: Identify the gas - law

This is a Charles's law problem ($\frac{V_1}{T_1}=\frac{V_2}{T_2}$), where $V$ is volume and $T$ is temperature.

Step2: List given values

$V_1 = 35.0\ L$, $T_1=293\ K$, $T_2 = 318\ K$.

Step3: Rearrange the formula for $V_2$

$V_2=\frac{V_1T_2}{T_1}$.

Step4: Substitute values

$V_2=\frac{35.0\ L\times318\ K}{293\ K}$.

Step5: Calculate

$V_2=\frac{11130}{293}\ L\approx38.0\ L$.

Answer:

$38.0\ L$