ben walks 500 meters from his house to the corner store. he then walks back toward his house but stops to…

ben walks 500 meters from his house to the corner store. he then walks back toward his house but stops to talk to a neighbor when he is 200 meters from the corner store. if it takes ben 910 seconds from the time he leaves his house until he stops to talk to his neighbor, what is his average velocity? (round your answer to the nearest tenth of a meter per second.) bens average velocity is m/s.

ben walks 500 meters from his house to the corner store. he then walks back toward his house but stops to talk to a neighbor when he is 200 meters from the corner store. if it takes ben 910 seconds from the time he leaves his house until he stops to talk to his neighbor, what is his average velocity? (round your answer to the nearest tenth of a meter per second.) bens average velocity is m/s.

Answer

Explanation:

Step1: Determine displacement

Displacement is the straight - line distance from the starting point to the ending point. Ben starts at his house. He walks 500 meters to the store and then back 300 meters (500 - 200) when he stops to talk to a neighbor. So the displacement $d=500 - 300=200$ meters towards the store.

Step2: Recall average velocity formula

The formula for average velocity is $v=\frac{d}{t}$, where $d$ is displacement and $t$ is time. Here, $d = 200$ meters and $t = 910$ seconds.

Step3: Calculate average velocity

$v=\frac{200}{910}\approx0.2$ m/s

Answer:

$0.2$ m/s