a bicycle tire has a volume of 1.0 l at 22°c. if the temperature of the tire is increased to 52°c, what is…

a bicycle tire has a volume of 1.0 l at 22°c. if the temperature of the tire is increased to 52°c, what is the resulting volume of the tire? type in your answer using the correct number of significant figures. use the formula for charles law: $\frac{v_1}{t_1}=\frac{v_2}{t_2}$

a bicycle tire has a volume of 1.0 l at 22°c. if the temperature of the tire is increased to 52°c, what is the resulting volume of the tire? type in your answer using the correct number of significant figures. use the formula for charles law: $\frac{v_1}{t_1}=\frac{v_2}{t_2}$

Answer

Answer:

1.1 L

Explanation:

Step1: Convert temperatures to Kelvin

$T_1 = 22 + 273 = 295$ K, $T_2=52 + 273 = 325$ K

Step2: Rearrange Charles' Law for $V_2$

$V_2=\frac{V_1T_2}{T_1}$

Step3: Substitute values

$V_2=\frac{1.0\ L\times325\ K}{295\ K}\approx1.1\ L$