blue light waves have more energy than red light waves. which of these situations most likely produces a…

blue light waves have more energy than red light waves. which of these situations most likely produces a photoelectric effect? you may assume that the same metal is used in each situation. check all that apply. shining dim red light on a strip of metal shining bright red light on a strip of metal shining dim blue light on a strip of metal shining bright blue light on a strip of metal done

blue light waves have more energy than red light waves. which of these situations most likely produces a photoelectric effect? you may assume that the same metal is used in each situation. check all that apply. shining dim red light on a strip of metal shining bright red light on a strip of metal shining dim blue light on a strip of metal shining bright blue light on a strip of metal done

Answer

Brief Explanations:

The photoelectric effect occurs when photons with sufficient energy strike a metal surface. Blue - light waves have more energy than red - light waves. For the photoelectric effect to happen, the photons must have energy greater than the work function of the metal. Since blue light has higher energy photons compared to red light, both dim and bright blue light can potentially have enough energy to cause the photoelectric effect, while red light (both dim and bright) likely does not have enough energy as its photons are less energetic.

Answer:

C. shining dim blue light on a strip of metal D. shining bright blue light on a strip of metal