6. a bottle weighs 50 g when empty and 98.6 g when filled with water. if 28.8 g of a granulated metal (sp…

6. a bottle weighs 50 g when empty and 98.6 g when filled with water. if 28.8 g of a granulated metal (sp gr. = 4) are placed in the bottle and the bottle is filled with water, the total weight is 118.4 g. what is the weight of water displaced by the metal?

6. a bottle weighs 50 g when empty and 98.6 g when filled with water. if 28.8 g of a granulated metal (sp gr. = 4) are placed in the bottle and the bottle is filled with water, the total weight is 118.4 g. what is the weight of water displaced by the metal?

Answer

Explanation:

Step1: Find weight of water when bottle is full initially

The weight of water when the bottle is full initially is the weight of the full - water bottle minus the weight of the empty bottle. So, $98.6 - 50=48.6$ g.

Step2: Find weight of water and metal together

We know the weight of the metal is $28.8$ g and the total weight of the bottle with metal and water is $118.4$ g. Let the weight of water in the bottle with metal be $x$. Then the weight of the empty bottle plus the weight of water plus the weight of metal is $118.4$ g. The weight of the empty bottle is $50$ g and the weight of metal is $28.8$ g. So, $x=118.4-(50 + 28.8)=39.6$ g.

Step3: Calculate weight of displaced water

The weight of displaced water is the weight of water when the bottle was full initially minus the weight of water when the metal is in the bottle. So, $48.6-39.6 = 9$ g.

Answer:

$9$ g