a box experiencing a gravitational force of 600 n is being pulled to the right with force of 250 n. a 25 n…

a box experiencing a gravitational force of 600 n is being pulled to the right with force of 250 n. a 25 n frictional force acts on the box as it moves to the right. what is the net force in the y - direction? 0 n 25 n 225 n 250 n

a box experiencing a gravitational force of 600 n is being pulled to the right with force of 250 n. a 25 n frictional force acts on the box as it moves to the right. what is the net force in the y - direction? 0 n 25 n 225 n 250 n

Answer

Answer:

0 N

Explanation:

Step1: Analyze forces in y - direction

The gravitational force acts downwards and there is an equal and opposite normal force acting upwards. In the vertical (y - direction), the box is not accelerating vertically. So, the net force in the y - direction is the sum of the gravitational force and the normal force. Since the box is on a flat surface and not moving vertically, the normal force $N$ balances the gravitational force $F_g$. Mathematically, $F_{net,y}=N - F_g$. And $N = F_g$, so $F_{net,y}=F_g - F_g=0$ N. The pulling force and frictional force act in the horizontal (x - direction) and do not contribute to the net force in the y - direction.